a/\(\frac{13}{11}.\frac{22}{26}-x^2=\frac{7}{16}\)

\(\Rightarrow1-x^2=\frac{7}{16}\)

\(\Rightarrow x^2=\frac{9}{16}\)

\(\Rightarrow x=\orbr{\begin{cases}\frac{3}{4}\\-\frac{3}{4}\end{cases}}\)

\(a,\frac{13}{11}.\frac{22}{26}-x^2=\frac{7}{16}\)

\(1-x^2=\frac{7}{16}\)

\(x^2=1-\frac{7}{16}=\frac{9}{16}\)

\(\Rightarrow\orbr{\begin{cases}x=\frac{3}{4}\\x=-\frac{3}{4}\end{cases}}\)

\(b,x^2+-\frac{9}{25}=\frac{2}{5}.\frac{8}{5}\)

\(x^2+-\frac{9}{25}=\frac{16}{25}\)

\(x^2=\frac{16}{25}--\frac{9}{25}=1\)

\(\Rightarrow\orbr{\begin{cases}x=1\\x=-1\end{cases}}\)

học tốt ~~~

a/ \(\frac{13}{11}.\frac{22}{26}-x^2=\frac{7}{16}\)

\(\Rightarrow\)\(1-x^2=\frac{7}{16}\)

\(\Rightarrow\)\(x^2=1-\frac{7}{16}\)

\(\Rightarrow\)\(x^2=\frac{9}{16}\)

\(\Rightarrow\)\(x^2=\left(\frac{3}{4}\right)^2\)

\(\Rightarrow\)\(x=\frac{3}{4}\)

b, \(x^2+\frac{-9}{25}=\frac{2}{5}.\frac{8}{5}\)

\(\Rightarrow x^2+\frac{-9}{25}=\frac{16}{25}\)

\(\Rightarrow x^2=\frac{16}{25}-\frac{-9}{25}\)

\(\Rightarrow x^2=\frac{25}{25}\)

\(\Rightarrow x^2=\left(\frac{5}{5}\right)^2=\left(\frac{-5}{5}\right)^2\)

\(\Rightarrow x=\frac{5}{5}=\frac{-5}{5}\)

\(\Rightarrow x=1=-1\)

\(\Rightarrow x=\pm1\)

A

A

C

a) x-29/6=13/6+10/12             b)15/26+x/13=46/25

    x-29/6=3                                        x/13=46/25-15/26

    x       =3+29/6                                x/13=821/650

    x       =47/6                                  x/650=821/650

                                                         x=821

c)2,8-x=6/5-3/5                     d)24/x:8/3=0,6

   2,8-x=2/5                             24/x:8/3=3/5

 14/5-x=2/5                             24/x      =3/5.8/3

        x=14/5-2/5                      24/x      =8/5

        x=12/5                            24/x      =24/15

                                                  x      =15

a, x - 29/6 = 13/6 + 10/12

x - 29/6 = 26/12+10/12

x - 29/6 =3

x = 3 + 29/6

x = 47/6

vậy x = 47/6

b, 15/26 + x/13 = 46/25

x/13 = 46/25 - 15/26

x/13 = 821/650

x ko thỏa mãn

\(a,\left(\frac{3}{8}+-\frac{3}{4}+\frac{7}{12}\right):\frac{5}{6}+\frac{1}{2}\)

   =  \(\left(-\frac{3}{8}+\frac{7}{12}\right):\frac{5}{6}+\frac{1}{2}\)

    = \(\frac{5}{24}:\frac{5}{6}+\frac{1}{2}\)

     = \(\frac{1}{4}+\frac{1}{2}\)

      =  \(\frac{3}{4}\)

b)\(-\frac{7}{3}.\frac{5}{9}+\frac{4}{9}.\left(-\frac{3}{7}\right)+\frac{17}{7}\)

    =\(-\frac{35}{27}+\left(-\frac{4}{21}\right)+\frac{17}{7}\)

   = \(-\frac{35}{27}+\frac{47}{21}\)

   =        \(\frac{178}{189}\)

c) \(\frac{117}{13}-\left(\frac{2}{5}+\frac{57}{13}\right)\)

  = \(\frac{117}{13}-\frac{311}{65}\)

 =       \(\frac{274}{65}\)

d) \(\frac{2}{3}-0,25:\frac{3}{4}+\frac{5}{8}.4\)

= \(\frac{2}{3}-\frac{1}{4}:\frac{3}{4}+\frac{5}{8}.4\)

= \(\frac{2}{3}-\frac{1}{3}+\frac{5}{2}\)

=     \(\frac{1}{3}+\frac{5}{2}\)

=         \(\frac{17}{6}\)

a) ( x- 13 ) x 25 = 0

=>  x - 13 = 0

=> x= 13

b) 2x - 5 = x+ 5

=> 2x - x = 5 + 5

=> x = 10

a,x=13

b,x=10

a, (x-13) x 25 = 0

=> x - 13 = 0

=> x = 13

vậy___

b, 2 * x - 5 = x + 5

=> 2 * x = x + 5 + 5

=> 2 * x = x + 10

=> 2 * x - x = 10

=> x * (2 - 1) = 10

=> x * 1 = 10

=> x = 10

vậy___

Bài 1: Tìm x biết

a) x - 50 : 25 = 8     

x- 2 = 8 

x= 8+2

x=10

b) (x + 40).15 = 75.24

x+40 = 75.24:15

x+40 = 70

x= 30

c) (x - 32) - 15 = 0

x- 31 = 15

x= 15+ 31

x = 46

d) 1234 : x = 2

x= 1234:2

x = 617

e) (x - 34).26 = 0

x- 34 = 0: 26

x= 0 + 34

x= 34

f) 152 + (x + 231) : 2 = 358

(x+231):2 = 358- 152

(x+231):2 = 206

x+ 231 = 206*2

x= 412 - 231

x= 181 

1.

a) x - 50 : 25 = 8

x - 2 = 8

x = 10

b) (x + 40) . 15 = 75 . 24

x + 40 = 75 . 24 : 15

x + 40 = 120

x = 80

c) (x - 32) - 15 = 0

x - 32 = 15

x = 47

d) 1234 : x = 2

x = 617

e) (x - 34) . 26 = 0

Thỏa mãn điều kiện x - 34 = 0

x = 34

f) 152 + (x + 231) : 2 = 358

(x + 231) : 2 = 206

x + 231 = 412

x = 181

2.

a) 45 . (2 . x - 4) . 13 = 0

Thỏa mãn điều kiện 2 . x - 4 = 0

x = 2

b) 5 . x - 38 : 19 = 13

5 . x - 2 = 13

5 . x = 15

x = 3

c) 100 - 3 . (8 + x) = 1

3 . (8 + x) = 99

8 + x = 33

x = 25

d) [(x + 12) - 17] : 5 = 4

(x + 12) - 17 = 20

x + 12 = 37

x = 25

e) 84 - 4 . (2 . x + 1) = 48

4 . (2 . x + 1) = 36

2 . x + 1 = 9

2 . x = 8

x = 4

Bài 1: Tìm x biết

a) x - 50 : 25 = 8

<=> x - 2 = 8

<=> x = 10

Vậy x = 10

b) (x + 40).15 = 75.24

<=> x + 40 = 120

<=> x = 30

Vậy x = 30

c) (x - 32) - 15 = 0

<=> x - 32 = 15

<=> x = 47

Vậy x = 47

d) 1234 : x = 2

<=> x = 617

Vậy x = 617

e) (x - 34).26 = 0

<=> x - 34 = 0

<=> x = 34

Vậy x = 34

f) 152 + (x + 231) : 2 = 358

<=> (x + 231) : 2 = 206

<=> x + 231 = 412

<=> x = 181

Vậy x = 181

Bài 2: Trong tập hợp số tự nhiên, tìm x biết:

a) 45.(2.x - 4).13 = 0

<=> 2x - 4 = 0

<=> x = 2

Vậy x = 2

b) 5.x - 38 : 19 = 13

<=> 5x - 2 = 13

<=> x = 3

Vậy x = 3

c) 100 - 3.(8 + x) = 1

<=> 3(8 + x) = 99

<=>8 + x = 33

<=> x = 25

Vậy x = 25

d) [(x + 12)] - 17] : 5 = 4

<=> (x + 12) - 17 = 20

<=> x + 12 = 37

<=> x = 25

Vậy x = 25

e) 84 - 4.(2.x + 1) = 48

<=> 4(2x + 1) = 36

<=> 2x + 1 = 9

<=> x = 4

Vậy x = 4

Học tốt nhá :))

a, \(x+\dfrac{1}{3}=\dfrac{7}{26}-\dfrac{-13}{6}\)

\(\Rightarrow x+\dfrac{1}{3}=\dfrac{95}{39}\)

\(\Rightarrow x=\dfrac{95}{39}-\dfrac{1}{3}\)

\(\Rightarrow x=\dfrac{50}{21}\)

a, ( x + 1 ) + ( x + 2 ) + ... + ( x + 199 ) = 0

x + 1 + x + 2 + ... + x + 199 = 0

( x + x + ... + x ) + ( 1 + 2 + ... + 199 ) = 0 

199x + 19900 = 0

199x = 0 - 19900

199x = -19900

x = -19900 : 199

x = -100

Vậy ...

b, ( x - 30 ) + ( x - 29 ) + ( x - 28 ) = 11

x - 30 + x - 29 + x - 28 = 11

( x + x + x ) - ( 30 + 29 + 28 ) = 11

3x -  87 = 11

3x = 11 + 87 

3x = 98

x = \(\frac{98}{3}\)

Vậy ... 

123 - 3 ( x + 4 ) = 23

3 ( x + 4 ) = 123 - 23

3 ( x + 4 ) = 100

x + 4 = \(\frac{100}{3}\)

x = \(\frac{100}{3}-4\)

x = \(\frac{88}{3}\)

Vậy ...

a, 35 ⋮ (x+3) => (x+3) ∈ Ư(35) = {1;5;7;35} => x ∈ {2;4;32}

b, (x+7) ⋮ 25 và x < 100

Vì (x+7) ⋮ 25 => x+7 ∈ B(25) = {0;25;50;75;...}

Mà x < 100 => x+7 ∈ {0;25;50;75}

=> x ∈ {18;43;68}

c, (x+13) ⋮ (x+1)

Ta có: x+13 = x+1+12

Vì (x+1) ⋮ (x+1) nên để (x+13) ⋮ (x+1) thì 12 ⋮ (x+1)

=> (x+1) ∈ Ư(12) = {1;2;3;4;6;12} => x ∈ {0;1;2;3;5;11}

d, 91 ⋮ x; 26 ⋮ x và 10 < x < 30

Vì 91 ⋮ x; 26 ⋮ x => x ∈ ƯC(26;91)

Ta có: 26 = 2.13; 91 = 7.13

=> ƯCLN(26;91) = 13

=> x ∈ Ư(13) = {1;13}

Mà 10 < x < 30 => x = 13

e, (x+2) ⋮ 10, (x+2) ⋮ 15, (x+2) ⋮ 25 và x < 200

Vì (x+2) ⋮ 10, (x+2) ⋮ 15, (x+2) ⋮ 25 nên (x+2) ∈ BC(10;15;25)

Ta có: 10 = 2.5; 15 = 3.5; 20 =  2 2 . 5

=> BCNN(10;15;20) =  2 2 . 3 . 5 = 60

=> (x+2) ∈ B(60) = {0;60;120;180;...}

Mà x < 200 => x ∈ {58;118;178}